4. When aqueous solutions of lead(II) ion are treated with potassium chromate solution, a bright yellow precipitate of lead(II) chromate, PbCrO4, forms. How many grams o lead chromate form when a 1.00-g sample of Pb(NO3)2 is added to 25.0mL of 1.00M K2CrO4 solution

Lead chromate form = 0.97 g

Explanation:

The Balanced chemical equation of the given reaction is as follows

              K₂CrO₄ + Pb(NO₃)₂ → PbCrO₄ + 2 KNO₃

Given that

        Mass of Pb(NO₃)₂ = 1 g

Mole of 25 ml of 1.00 (M)  K₂CrO₄

                   Mole =   25 x 1 milimol = 25 x 10⁻³

Using mole ratio method to find limiting reagent

Hence K₂CrO₄(potassium chromate) is a limiting reagent.

So lead chromate formed = mole X molar mass

                                           = 0.003 X 323.19 g

                                           = 0.97 g

∴ 0.97 g lead chromate form when a 1.00-g sample of Pb(NO₃)₂ is added to 25.0 ml of 1.00 M K₂CrO₄ solution.

what is the general relationship between a galaxy's distance from earth and its speed?

the answer is:

the farther away a galaxy is from us, the faster it is moving away from us.

a. energy is absorbed in the reaction.

if in a given reaction the energy of products is greater than the energy of reactants it means that reaction is endothermic and during the reaction, the energy is absorbed by reactants. in an endothermic reaction, the products have more stored chemical energy than the reactants. and in this reaction the reactants are more stable than products before the compounds with less energy are always more stable.