A mixture of 0.10 molmol of NONO, 0.050 molmol of H2H2, and 0.10 molmol of H2OH2O is placed in a 1.0-LL vessel at 300 KK. The following equilibrium is established:
2NO(g)+2H2(g)←→N2(g)+2H2O(g)2NO(g)+ 2H2(g)←→N2(g)+2H2O(g)
At equilibrium [NO]=0.062M[NO]=0.062M.
Part A:
Calculate the equilibrium concentration of H2
Part B:
Calculate the equilibrium concentration of N2N2.
Part C:
Calculate the equilibrium concentration of H2OH2O.
Part D:
Calculate KcKc.
Answers: 2
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