At standard temperature and pressure (0 ∘C∘C and 1.00 atmatm ), 1.00 molmol of an ideal gas occupies a volume of 22.4 LL. What volume would the same amount of gas occupy at the same pressure and 35 ∘C∘C ?

The volume would be 24, 3 L.

Explanation:

We apply the ideal gas law, we convert the unit of temperature in celsius to degrees Kelvin, we clear the volume of the formula and we use the constant R of the ideal gases that has a value of 0.082 l atm / K mol:

0°C= 273 K ---> 35°C= 273 + 35= 308K

PV=nRT   ---> V= nRT/P

V= 1 mol x 0.082 l atm / K mol x 308 K/ 1 atm= 25, 256 L

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