What is the final pressure when 100.0mL of a gas at 5.00 atm is compressed to 25.0mL at constant temperature?
(help! timed Test)
A.) 1.25 atm
B.) 500 atm
C.) 10.0 atm
D.) 20.0 atm

D) 20.0 atm

Explanation:

To solve this problem, we can apply Boyle's law, which states that:

"For a constant mass of an ideal gas kept at constant temperature, the pressure of the gas is inversely proportional to the volume of the gas".

Mathematically:

where

p is the gas pressure

V is the volume of the gas

The equation can also be rewritten as

where in this problem:

is the initial pressure of the gas

is the initial volume of the gas

is the final volume of the gas

Solving for p2, we find the final pressure of the gas:

answer: a tank of height h is filled with water and sits on the ground. water squirts from a hole at a height y above the ground and has a range r. for two y values, 0 and h, r is zero. determine the value of y for which the range will be a maximum.

explanation:

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml