Dr. Moore has discovered a new vaccine composed of carbon, hydrogen, and oxygen. When the product was purified and sent off for elemental analysis it gave the following mass percents: 68.85% C, 4.95% H. Determine the empirical formula of this vaccine.

C4H3O

Explanation:

Data obtained from the question include:

Carbon (C) = 68.85%

Hydrogen (H) = 4.95%

Since the vaccine contains carbon, hydrogen and oxygen, the remaining percentage will be for oxygen. The percentage of oxygen will be:

Oxygen (O) = 100 - (68.85 + 4.95)

= 26.2%

The empirical formula for the vaccine can be obtained as follow:

Carbon (C) = 68.85%

Hydrogen (H) = 4.95%

Oxygen (O) = 26.2%

Divide the above by their individual molar mass as shown below:

C = 68.85/12 = 5.7375

H = 4.95/1 = 4.95

O = 26.2/16 = 1.6375

Next, divide by the smallest number as shown below:

C = 5.7375/1.6375 = 4

H = 4.95/1.6375 = 3

O = 1.6375/1.6375 = 1

Therefore, the empirical formula for the vaccine is C4H3O

c)red bank

explanation:

red bank is a borough in monmouth county, new jersey, incorporated in 1908 and located on the navesink river, the area's original transportation route to the ocean and other ports.

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3