In a laboratory experiment, a student titrates 10.0 mL of acetic acid, CH3COOH, solution with 0.5 M NaOH. The endpoint was reached when 46.00 mL of 0.50 M NaOH were delivery. What was the concentration of acetic acid in the solution

Concentration of acetic acid=2.3mol/L

Explanation:

Write the balanced chemical reacion:

N1 and N2 normality of CH3COOH and NaOH respectively;

V1 and V2 volume of CH3COOH and NaOH respectively and they are taken upto end point of titration;

we have given molarity but we need normality;

but in case of NaOH and CH3COOH n-factor is 1 for each.

hence

normality=molarity;

Concentration of acetic acid=2.3mol/L

a police officer and a ambulance

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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