"The elementary reaction 2 NO2(g) → 2 NO(g) + O2(g) is second order in NO2 and the rate constant at 600 K is 6.77 × 10-1 M-1s-1. The reaction half-life at this temperature when [NO2]0 = 0.45 M is s."

Answer : The half-life at this temperature is, 3.28 s

Explanation :

To calculate the half-life for second order the expression will be:

When,

= half-life = ?

= initial concentration = 0.45 M

k = rate constant =

Now put all the given values in the above formula, we get:

Therefore, the half-life at this temperature is, 3.28 s

it would be b. 6co2 + 6h2o --> c6h12o6 + 6o2