Zinc reacts with hydrochloric acid according to the reaction equation Zn ( s ) + 2 HCl ( aq ) ⟶ ZnCl 2 ( aq ) + H 2 ( g ) How many milliliters of 6.50 M HCl ( aq ) are required to react with 2.55 g Zn ( s ) ?

12.0 milliliters of 6.50 M HCl ( aq ) are required to react with 2.55 g Zn.

Explanation:

moles =

moles of zinc =

The balanced chemical equation is :

According to stoichiometry:

1 mole of zinc reacts with = 2 moles of HCl

Thus 0.0390 moles of zinc reacts with = moles of HCl

To calculate the volume for given molarity, we use the equation:

    .....(1)

Molarity of solution = 6.50 M

Volume of solution = ?

Putting values in equation 1, we get:

Thus 12.0 ml of 6.50 M HCl ( aq ) are required to react with 2.55 g Zn

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.