In the reaction below, 2.00 g of Al will react with how many milliliters of 0.500 M HCI?
2 Al(s) + 6 HCl(aq) → 2 AlCl3 (aq) + 3 H2(g)

420 mL

Explanation:

Given data:

Mass of Al = 2.00 g

Molarity of HCl = 0.500 M

Millilitres of HCl react= ?

Solution:

Chemical equation:

2Al + 6 HCl    →    2AlCl₃ + 3H₂

Number of moles of Al:

Number of moles = mass/ molar mass

Number of moles = 2.00 g/ 27 g/mol

Number of moles = 0.07 mol

Now we will compare the moles of Al with HCl.

                        Al             :             HCl

                         2             :               6

                      0.07          :           6/2×0.07 = 0.21 mol

Millilitres of HCl:

Molarity = number of moles / Volume in L

0.500 M = 0.21 mol / Volume in L

Volume in L = 0.21 mol / 0.500 M

Volume in L = 0.42 L

L to mL:

1 L = 1000 mL

0.42 L × 1000 mL / 1L

420 mL

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