Using Charles law if the volume of a gas is 5.0 L when the temperature is 5.0C what will the new volume be if the temperature is raised to 10C and the pressure remains the same

The answer to your question is   V2 = 5.09 l

Explanation:

Data

Volume 1 = V1 = 5.0 L

Temperature 1 = T1 = 5°C

Volume 2 = V2 = ?

Temperature 2 = T2 = 10°C

Formula (Charles law)

             V1/T1 = V2/T2

-Solve for V2

                  V2 = V1T2 / T1

-Convert temperature to °K

T1 = 5 + 273 = 278°K

T2 = 10 + 273 = 283°K

-Substitution

                 V2 = (5)(283) / (278)

-Simplification

                 V2 = 1415 / 278

-Result

                 V2 = 5.09 l

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