4.00 L of a gas is known to contain 0.975 mol. If the amount of gas is increased to 3.80 mol, what new volume will result?

The new volume is 15.59L

Explanation:

Given:

Initial volume, V₁ = 4L

Initial number of moles, n₁ = 0.975 mol

Final number of moles, n₂ = 3.8 mol

New volume, V₂ = ?

According to Avogadro's law:

Substituting the values we get:

Therefore, the new volume is 15.59L

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml