The reaction below has a Kp value of 3.3 × 10-5. What is the value of Kc for this reaction at 700 K? Note: Type the correct answer with 1 decimal place and in scientific notation. Example: 6.5 x 10-15 should be input as 6.5E-15. Example 2: 5.4 x 10-6 should be input at 5.4E-06.

This is an incomplete question, here is a complete question.

The reaction below has a Kp value of 3.3 × 10⁻⁵. What is the value of Kc for this reaction at 700 K?

Answer : The value of is,

Explanation :

The relation between and is:

where,

= equilibrium constant at constant pressure  =

R = gas constant = 0.0821 L.atm/mol.K

T = temperature = 700 K

= change in number of gaseous moles = Product moles - Reactant moles = (2+1) - (2) = 3 - 1 = 1 mol

= equilibrium constant

Now put all the given values in the above expression, we get:

Therefore, the value of is,

the answer is a! (2.9 x 10^-18 j) hope i could someone. : )