The pressure of a balloon made of a stretchy material is held constant at
2 atm. If the initial volume is 250 mL at room temperature (25 ˚C), what
would be the final volume at 50 ˚C?

New volume is 271 mL

Explanation:

To determine the volume for a gas, when the pressure remains constant we follow this ratio:

V₁ / T₁ = V₂ / T₂

Remember the Ideal Gases Law → P . V = n . R . T

That's why we propose V / T

We need to determine the Absolute T°

25°C + 273 = 298 K

50°C + 273 = 323 K

We convert the volume from mL to L → 250 mL . 1L / 1000 mL = 0.250L

Now we replace: 0.250L / 298K = V₂ / 323K

V₂ = (0.250L / 298K) . 323K  → 0.271 L

In conclussion volume of a gas will be increased, while the temperature is also increased and the pressure remains constant.

The final volume is 271 mL

Explanation:

Step 1: Data given

The initial pressure = 2 atm

The pressure will be kept constant

The initial volume = 250 mL = 0.250 L

The initial temperature = 25°C = 298 K

The final temperature = 50 °C = 323 K

Step 2: Calculate the final volume

V1/T1 = V2/T2

⇒with V1 = the initial volume = 0.250 L

⇒with T1 = the initial temperature = 25 °C = 298 K

⇒with V2 = the final volume = TO BE DETERMINED

⇒with T2 = the final temperature = 50 °C = 323 K

0.250 L / 298 K = V2 / 323 K

V2 = (0.250 /298) *323

V2 = 0.271 L = 271 mL

The final volume is 271 mL

your answer would be a. 12.5 kg