A frisbee is moving at 11 m/s and has 3.6j of energy. how much does it weigh?

0.06 kg

Explanation:

Given data:

Mass of frisbee = ?

Velocity of frisbee  = 11 m/s

Energy of frisbee = 3.6 j

Solution:

K.E = 1/2 mv²

Now we will put  the values in this formula.

3.6 J = 1/2 m(11m/s)²

3.6 j = 0.5 ×121m²/s² × m

3.6 j = 60.5 m²/s² × m

m = 3.6 j/60.5 m²/s²

m= 0.06 j.m⁻².s²

j = Kg.m².s⁻²

m= 0.06 Kg.m².s⁻² .m⁻².s²

m = 0.06 kg

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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