When 38.0 g of N2 is reacted with H2 and 40.12 g of NH3 are produced, what is the percent yield?

52.80 % is the percent yield of the reaction.

Explanation:

Mass of nitrogen gas = 38.0 g

Moles of nitrogen =

According to reaction, 1 moles of nitrogen gas gives 2 moles of ammonia, then 2.235 moles of nitrogen  will give:

 ammonia

Mass of 4.470  moles of ammonia

= 4.470 mol × 17 g/mol = 75.99 g

Theoretical yield of ammonia = 217.8 g

Experimental yield of ammonia = 40.12 g

The percentage yield of reaction:

52.80 % is the percent yield of the reaction.

oh it is true if thats what you are asking

8 m/s because for him to get the same amount of energy as ray is putting out, bobby, who weighs half as much as ray, needs to run twice as fast.