When the following molecular equation is balanced using the smallest possible integer coefficients, the values of these coefficients are:

aluminum oxide (s) + sulfuric acid (aq) > aluminum sulfate (aq) + water (l)

Does a reaction occur when aqueous solutions of ammonium carbonate and chromium(III) nitrate are combined?

1. Al2O3 + 3H2SO4 —> Al2(SO4)3 + 3H2O

The coefficients are: 1, 3, 1, 3

2. Yes, reaction occurs when ammonium carbonate and chromium(III) nitrate are combined.

The balanced equation for the reaction is given below:

3(NH4)2CO3 + 2Cr(NO3)3 —> 6NH4NO3 + Cr2(CO3)3

The coefficients are: 3, 2, 6, 1

Explanation:

1. The word equation is given below:

aluminum oxide(s) + sulfuric acid(aq) -> aluminum sulfate(aq) + water (l)

The above can be written as:

Al2O3 + H2SO4 —> Al2(SO4)3 + H2O

Now we can balance the equation as follow:

There are 3 atoms of SO4 on the right side and 1 atom on the left. It can be balance by putting 3 in front of H2SO4 as shown below:

Al2O3 + 3H2SO4 —> Al2(SO4)3 + H2O

There are 6 atoms of H on the left side and 2 atoms on the right. It can be balance by putting 3 in front of H2O as shown below:

Al2O3 + 3H2SO4 —> Al2(SO4)3 + 3H2O

Now the equation is balanced

The coefficients are: 1, 3, 1, 3

2. Yes, reaction occurs when ammonium carbonate and chromium(III) nitrate are combined.

The equation for the reaction is given below:

(NH4)2CO3 + Cr(NO3)3 —> NH4NO3 + Cr2(CO3)3

We can balance the equation above as follow:

There are 2 atoms of Cr on the right side and 1 atom on the left. It can be balance by putting 2 in front of Cr(NO3)3 as shown below:

(NH4)2CO3 + 2Cr(NO3)3 —> NH4NO3 + Cr2(CO3)3

Now, there are 6 atoms of NO3 on the left side and 1 on the right side. It can be balance by putting 6 in front of NH4NO3 as shown below:

(NH4)2CO3 + 2Cr(NO3)3 —> 6NH4NO3 + Cr2(CO3)3

Now, there are 2 atoms of NH4 on the left side and 6 atoms on the right. It can be balance by putting 3 in front of (NH4)2CO3 as shown below:

3(NH4)2CO3 + 2Cr(NO3)3 —> 6NH4NO3 + Cr2(CO3)3

Now the equation is balanced.

The coefficients are: 3, 2, 6, 1

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.