1. A beam of light has a frequency of 6.41 x 1014 Hz. What is the wavelength of the light in meters?
C = 3.0 x 108 m/s; h = 6.626 x 10-34 ;s

The answer for the following problem is mentioned below.

Explanation:

Energy:

The capacity to do work

Given:

frequency of the light (ν) = 6.41 × 10^14 Hz

Also given;

c = 3×10^8 m/s

h = 6.626 × 10^-34 J/s

Where,

h represents the Planck's constant

the value of h is 6.626 × 10^-34 J/s

c represents the speed of the light in the vacuum

We know;

E = h × ν

E  represents the energy of the light.

E = 6.626 × 10^-34 × 6.41 × 10^14

E = 42.47 × 10^ -20 J

Given:

energy (E) = 42.47 × 10^-20 J (i.e.) from the above calculation

c = 3×10^8 m/s

h = 6.626×10^-34 J/s

We know;

E =(h×c)÷λ

λ =

λ =

λ = 0.468 × 10^-6 m

Therefore the wavelength of the light is 0.468 × 10^-6 meters

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !