A 1.00 liter sample of H2 gas is collected at 25.0°C and 202.6 kPa. What volume does this sample occupy at STP

The answer to your question is 2 liters

Explanation:

Data

Volume 1 = 1 l                                  Volume 2 = ?

Temperature 1 = 25°C                    Temperature 2 = 25°C

Pressure 1 = 202.6 kPa                  Pressure 2 = 101.3 kPa

Process

As Temperature 1 is equal to temperature 2 we can use Boyle's law to solve this problem.

              Pressure 1 x Volume 1 = Pressure 2 x Volume 2

-Solve for Volume 2

              Volume 2 = Pressure 1 x Volume 1 / Pressure 2

-Substitution

             Volume 2 = (202.6 kPa x 1) / 101.3

-Simplification

            Volume 2 = 202.6 / 101.3

-Result

            Volume 2 = 2 l

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)