It requires 0.0780L of a 0.12 M HCl solution to completely neutralize 0.0280L of an unknown LiOH solution. What is the concentration of the unknown LiOH solution?

C₂ = 0.334 M

Explanation:

Given data:

Volume of HCl  = 0.0780 L

Concentration of HCl = 0.12 M

Volume of LiOH = 0.0280 L

Concentration of LiOH = ?

Solution:

Formula:

C₁V₁ = C₂V₂

C₁ = Concentration of HCl

V₁ = Volume of HCl

C₂ = Concentration of LiOH

V₂ = Volume of LiOH

Now we will put the values in formula.

C₁V₁ = C₂V₂

0.12 M × 0.0780 L =  C₂ × 0.0280 L

0.00936  M.L = C₂ × 0.0280 L

C₂ = 0.00936 M.L/0.0280 L

C₂ = 0.334 M

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer

a