Consider the chemical equation for the production of water: 2 H2+O2→2 H2O. If 100 grams of oxygen gas are used, what would the percent yield be if 75 g of H2O was produced? Show your work.

The percentage yield of water is 66.67%.

Explanation:

Mass of oxygen gas = 100 g

Moles of oxygen gas =

According to reaction, 1 mole of oxygen gives 2 moles of water, then 3.125 moles of oxygen will give:

Mass of 6.25 moles of water :

6.25 mol × 18 g/mol = 112.5 g

Theoretical yield of water = 112.5 g

Experimental yield of water = 75 g

Percentage yield :

The percentage yield of water is 66.67%.

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