Consider the reaction: Cu(s)+2 AgNO3(aq) = 2 Ag(s)+Cu(NO3)2(aq)

If 3.00 moles of copper metal react:

a) How many moles of silver metal will be produced?

b) How many grams of silver metal will be produced?

c) How many moles of copper (II) nitrate will be produced?

d) How many grams of copper (II) nitrate will be produced?

Explanation:

a)

According to the reaction equation:

1 mole of copper produces two moles of silver metal

3 moles of copper metal will produce 3×2/1 = 6 moles of silver metal

b)

Mass of silver produced= number of moles × molar mass

Mass of silver produced= 6×108 = 648g of silver

c)

1 mole of Cu produced 1 mole of copper II nitrate

3 moles of copper will produce 3×1/1 = 3moles of copper Ii nitrate

d)

Molar mass of copper II nitrate= 64 + 2(14+3(16))= 188gmol-1

Mass of copper II nitrate= 3× 188 = 564g of copper II nitrate

step-by-step explanation:

whole numbers, zero or greater