If the compound below containing three types of alcohols were exposed to only 1 equivalent of hcl, what major product would you expect?

The question is incomplete. The image showing the compound and the options in the questions is attached.

B

Explanation:

If we closely examine the structure of the compound given in the question, we will notice that the reaction must involve the substitution of the hydroxyl group by chlorine in the parent molecule.

This occurs when the -OH group combines with H^+ to form -OH2^+ which is a good leaving group.

Compound B is formed because, when -OH2^+ leaves, a carbocation is created. This carbocation is stabilized by the alkyl groups attached to the carbon atom bearing the leaving group by +I inductive effect. This carbon atom bearing the leaving group is a tertiary carbon atom thus it forms a more stable carbocation. Hence the product formed.

1. 1 mole of anything contains 6.022x10^23 pieces  

d  

2. a  

3. c, number  

5. 1.24x10^24atoms / 6.022x10^23atoms/mole = 2moles h2 atoms  

6. fe2br3 mass = 2moles x mass fe + 3 moles x mass br  

molar mass = grams / number of moles = g/mole  

to find moles = g / molar mass  

to find mass = g = molar mass / moles

samuel de champlain. in 1608, king henry iv sponsored pierre dugua, sieur de mons and samuel de champlain as founders of the city of quebec with 28 men. this was the second permanent french settlement in the colony of canada.