Consider the following unbalanced reaction for the combustion of hexane: C6H14(g) + O2(g) --> CO2(g) + H2O (g)
Balance the equation and determine how many grams of CO 2 gas will form when 5.35 grams of C6H14 reacts with excess O2.

1. 2C6H14 + 19O2 —> 12CO2 + 14H2O

2. 16.42g

Explanation:

1. We'll begin by balancing the equation. This is illustrated below:

C6H14 + O2 —> CO2 + H2O

There are 6 atoms of C on the left side and 1 atom on the right. It can be balance by putting 6 in front of CO2 as shown below:

C6H14 + O2 —> 6CO2 + H2O

There are 14 atoms of H on the left side and 2 atoms on the right. It can be balance by putting 7 in front of H2O as shown below:

C6H14 + O2 —> 6CO2 + 7H2O

Now, there are a total of 19 atoms of O on the right side and 2 at on the left side. It can be balance by putting 19/2 in front of O2 as shown below:

C6H14 + 19/2O2 —> 6CO2 + 7H2O

Now multiply through by 2 to clear the fraction as shown below:

2C6H14 + 19O2 —> 12CO2 + 14H2O

Now the equation is balanced

2. 2C6H14 + 19O2 —> 12CO2 + 14H2O

Let us determine the mass of C6H14 that reacted and the mass of CO2 produced from the balanced equation.

This is illustrated below:

Molar Mass of C6H14 = (12x6) + (14x1) = 72 + 14 = 86g/mol

Mass of C6H14 from the balanced equation = 2 x 86 = 172g

Molar Mass of CO2 = 12 + (2x16) = 12 + 32 = 44g/mol

Mass of CO2 from the balanced equation = 12 x 44 = 528g

From the equation above,

172g of C6H14 produced 528g of CO2.

Therefore, 5.35g of C6H14 will produce = (5.35 x 528)/172 = 16.42g of CO2.

From the calculations made above, 16.42g of CO2 will be produced from 5.35g of C6H14

16.4 grams of Carbon dioxide (CO2) gas will be formed

2C6H14(g) + 19O2(g) --> 12CO2(g) + 14H2O (g)

Explanation:

Step 1: Data given

Mass of C6H14 = 5.35 grams

Molar mass C6H14 = 86.18 g/mol

Molar mass CO2 = 44.01 g/mol

Step 2: The unbalanced equation

C6H14(g) + O2(g) --> CO2(g) + H2O (g)

Step 3: The balanced equation

2C6H14(g) + 19O2(g) --> 12CO2(g) + 14H2O (g)

Step 4: Calculate moles hexane (C6H14)

Moles hexane = mass hexane / molar mass hexane

Moles hexane = 5.35 grams / 86.18 g/mol

Moles hexane = 0.0621 moles

Step 5: Calculate moles CO2

For 2 moles hexane we need 19 moles oxygen to produce 12 moles carbon dioxide and 14 moles water

For 0.0621 moles hexane we'll have 6*0.0621 = 0.3726 moles CO2

Step 6: Calculate mass CO2

Mass CO2 = 0.3726 moles * 44.01 g/mol

Mass CO2 = 16.4 grams

16.4 grams of Carbon dioxide (CO2) gas will be formed

- aluminum and copper chloride.

- the chloride ion to separate the aluminum from the oxygen so that the aluminum can react with the copper ions (and the water molecules).

answer is: nuclear fusion produces elements that are heavier than helium.

nuclei combine to form a heavier nucleus, releasing energy.  

for example, fusion of hydrogen atoms at the sun.  

this fusion nuclear reaction is in the inner core of the sun and hydrogen (atomic number 1) is conveted into helium (atomic number 2).  

the inner core is the central region of the sun and all solar energy is produced in the core by nuclear fusion.