_Mno2+_HCl _MnCl2+_H2O+_Cl2

Hey there!

MnO₂ + HCl → MnCl₂ + H₂O + Cl₂

Balance Cl.

1 on the left, 4 on the right. Add a coefficient of 4 in front of HCl.

MnO₂ + 4HCl → MnCl₂ + H₂O + Cl₂

Balance H.

4 on the left, 2 on the right. Add a coefficient of 2 in front of H₂O.

MnO₂ + 4HCl → MnCl₂ + 2H₂O + Cl₂

Balance O.

2 on the left, 2 on the right. Already balanced.

Balance Mn.

1 on the left, 1 on the right. Already balanced.

Our final balanced equation:

MnO₂ + 4HCl → MnCl₂ + 2H₂O + Cl₂

Hope this helps!

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)

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