A 4.00 L sample of a gas is heated from 20.0 K to 200.0 K. What will its final volume be?

40L

Explanation:

The following were obtained from the question:

V1 (initial volume) = 4L

T1 (initial temperature) = 20K

T2 (final temperature) = 200K

V2 (final volume) =?

Using the equation V1 /T1 = V2/T2, the final volume of the gas can easily be obtain as follow:

V1 /T1 = V2/T2

4/20 = V2/200

Cross multiply to express in linear form as shown below:

20 x V2 = 4 x 200

Divide both side by 20

V2 = (4 x 200) /20

V2 = 40L

The final volume of the gas is 40L

it can be observed without changing the identity of the object.

it depends on what substance you're talking about as well as many other factors. in quantum mechanics, the observation of particles affects the observers ability to measure certain properties. for example: you can know the velocity of a particle, but you can't know it's position; or you can know it's position, but not it's velocity. it's like trying to find out where a grain of sand is by throwing other grains of sand at it. once you find out where it is, it's been moved. it's also like trying to find an answer to the question of whether or not a tree falling in a forest makes a sound if nobody is there to hear it. paradoxically, the only way to find out is to be there and hear it.