Chemistry, 31.03.2020 21:57, ssjdudjdsloe8106

The neutralization sulfuric acid with sodium hydroxide yields
HSO4(aq) + Na2OH(aa)
H2SO4(aq) + NaOH(aq)
H2Na(1) + O2SO4(aq)
H2O(l) + Na2SO4(aq)

Answers: 2

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answered: Katyazamo

H2O(l) + Na2SO4(aq)

Explanation:

When sulphuric acid (H2SO4) is neutralized by sodium hydroxide (NaOH), the product formed are sodium sulphate (Na2SO4) and water (H2O). This is illustrated by the equation below:

NaOH + H2SO4 —> Na2SO4 + H20

Now we can balance the equation above as follow:

There are 2 atoms of Na on the right side and 1atom on the left side. It can be balance by putting 2 in front of NaOH as shown below:

2NaOH + H2SO4 —> Na2SO4 + H20

Now we have a total of 4 atoms of H on the left side and 2 atoms on the right side. It can be balance by putting 2 in front of H2O as shown below:

2NaOH + H2SO4 —> Na2SO4 + 2H20

Now the equation is balanced.

The product are Na2SO4 and H20

answered: Guest

assuming that your periodic table has eighteen columns, you should highlight the four elements in the third column from the left of the table.

explanation

neutral atoms of elements after calcium contain d electrons. the energy of d orbitals of a particular main shell lies between the energy of the s and p orbitals of the next main shell. for example, electrons in the $3d$ have energy higher than those in the $4 s$ orbital while lower than those of the $4 p$ orbital.

by the aufbau principle, electrons fill orbitals one at a time, starting from those of the lowest energy. the $4s$ orbital is therefore filled right after $3p$ orbitals and before $3 d$ orbitals.

potassium has electron configuration $[\text{ar}] 4 s^{1}$ and calcium $[\text{ar}] 4 s^{2}$ . the s orbital of a main shell holds a maximum of two electrons. the next element would thus have the electron configuration $[\text{ar}] 4 s^{2} \; 3d^{1}$ and satisfy the requirements.

a neutral atom of the element contains three electrons on top of the most recent noble gas element. it should thus be placed in the third column of the periodic table. both scandium and yttrium would satisfy the conditions. an aufbau diagram indicates that the 4f orbital is filled before the 5d. however, it appears that exceptions exists for both lanthanum and actinium. neutral atoms of the two d-block elements also demonstrate the $ns^{2} \; (n-1) p^{1}$ and should be highlighted as well.