How many grams HBr will be produced from 0.100 moles bromine reacted with excess hydrogen?

16.18 g HBr

Explanation:

We are given;

0.100 moles of Bromine

We need to determine the amount of HBr produced when bromine reacts with hydrogen;

First, we write the equation for the reaction;

H₂(g) + Br₂(l) → 2HBr

From the equation;

1 mole of bromine reacts with hydrogen to form 2 moles of HBr

Therefore;

Moles of HBr = 2 × moles of Bromine

                       = 2 × 0.100 moles

                        = 0.200 moles

Secondly, we determine the mass of HBr produced

Mass = Number of moles × molar mass

Molar mass of HBr = 80.91 g/mol

Thus;

Mass of HBr = 0.200 moles × 80.91 g/mol

                     = 16.182 g

                      = 16.18 g

Therefore, the mass of HBr is 16.18 g

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.