PLEASE HELP!! I have to pass this class! Anything!!

We'll have 8.0 moles Fe3O4 and 4.0 moles CO2

Explanation:

Step 1: data given

Number of moles Fe2O3 = 12.0 moles

Number of moles CO = 12.0 moles

Step 2: The balanced equation

3Fe2O3 +CO → 2Fe3O4 + CO2

Step 3: Calculate the limiting reactant

For 3 moles Fe2O3 we need 1 mol CO to produce 2 moles Fe3O4 and 1 mol CO2

Fe2O3 is the limiting reactant. It will completely be consumed (12.0 moles).

CO is in excess. There will react 12.0 / 3 = 4.0 moles

There will remain 12.0 - 4.0 = 8.0 moles

Step 4: Calculate moles products

For 3 moles Fe2O3 we need 1 mol CO to produce 2 moles Fe3O4 and 1 mol CO2

For 12.0 moles Fe2O3 we'll have 2/3 * 12.0 = 8.0 moles Fe3O4

For 12.0 moles Fe2O3 we'll have 12.0 / 3 = 4.0 moles CO2

We'll have 8.0 moles Fe3O4 and 4.0 moles CO2