Okay, so we had a chemistry lab on titrating an unknown weak acid into a known solution of a strong base (NaOH). This means, we slowly dripped around 10 mL of weak acid into the strong base solution. For a presentation, I'm asked for what would happen if we reversed this- as in, what would happen if instead, we dripped 10 mL of NaOH into a solution of the unknown weak acid.

Here's the exact question, What would be different about the weak acid titration if you were to put the unknown weak acid in the buret and titrate 10 mL of a known molarity NaOH solution? How would the titration curve be different?

Agas occupies 475 cm^3 at 313k. find its volume at 367k. you must show all of your work to receive credit. be sure to identify which of the gas laws you will be using

What is the vapor pressure of a solution with a benzene to octane?

One way in which the useful metal copper is produced is by dissolving the mineral azurite, which contains copper(ii) carbonate, in concentrated sulfuric acid. the sulfuric acid reacts with the copper(ii) carbonate to produce a blue solution of copper(ii) sulfate. scrap iron is then added to this solution, and pure copper metal precipitates out because of the following chemical reaction: (s) (aq) (s) (aq) suppose an industrial quality-control chemist analyzes a sample from a copper processing plant in the following way. he adds powdered iron to a copper(ii) sulfate sample from the plant until no more copper will precipitate. he then washes, dries, and weighs the precipitate, and finds that it has a mass of .