The equation for the metabolic breakdown of glucose (C6H12O6) is the same as the equation for the combustion of glucose in air: C6H12O6(s) + 6O2(g) → 6CO2(g) + 6H2O(l) Calculate the volume of CO2 produced at 37°C and 1.00 atm when 3.63 g of glucose is used up in the reaction.

Idid the calculation and i get 875,000,000 which can be written as 8.75 x 10^6?

The correct answer is d

Electron equations of the given changes are as follow,a)                              cu      →      cu⁺²  + 2e⁻b)                              mg⁺²  +  2 e⁻      →      mgc)                              cl⁻    →      cl  +  1e⁻d)                              s  +  2 e⁻    →      s²⁻e)                                o²⁻      →      o  +  2 e⁻f)                              p  +  3 e⁻    →      p³⁻g)                              fe²⁺    →      fe³⁺  + 1 e⁻h)                              s²⁻    →      s⁴⁺  +  6 e⁻