2 CO (g) + O2(g) -> 2 CO2 (g) The formation of CO2 from CO and oxygen, how many liters of CO2 are produced by the reaction of 8 mols of O2 with an excess of carbon monoxide

The answer to your question is volume = 358.4 L

Explanation:

Data

volume of CO₂ = ?

moles of O₂ = 8

moles of CO = excess

Balanced chemical reaction

                 2 CO  +  O₂   ⇒   2 CO₂

Process

1.- Calculate the moles of CO₂

                 1 mol of O₂ 2 moles of CO₂

                8 moles of O₂ x

                                      x = (8 x 2) / 1

                                      x = 16 moles of CO₂

2.- Calculate the volume of CO₂

                 1 mol of CO₂ 22.4 L

                16 moles of CO₂  x

                                    x = (16 x 22.4) / 1

                                    x = 358.4 L

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.