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At 100 degrees Celsius, the ion product for pure water is Kw= 51.3*10^-14. What is the pOH of water at this temperature? A) 7.00 B) 7.27 C) 6.14 D) 6.63 E) 7.86
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At 100 degrees Celsius, the ion product for pure water is Kw= 51.3*10^-14. What is the pOH of water...
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