Determine whether each cation is acidic or pH-neutral. For the cations that are acidic, write an equation that shows how the cation acts as an acid. a. ��!! b. ��! c. �!�!��! d. ��

THE COMPLETE QUESTION IS:

Determine whether each cation is acidic or pH-neutral. For those cations that are acidic, write an equation that shows how the cation acts as an acid . a. NH+4 b. Na+ c. Co3+ d. CH2NH+3

a. Acidic

b. neutral

c. Acidic

d. Acidic

Explanation:

a. NH4+ + H2O <==> NH3 + H3O+ (NH4+ is a conjugate acid of a weak base. Therefore it is acidic)

b. Neutral. Na+ is a cation of a strong base. Therefore it's pH is neutral.

c. Co(H2O)6³+ + H2O <==>CoH2O5(OH)²+ + H3O+

(Therefore Co+ is a weak acid since hydronium ion is formed.)

d. CH2NH3+ is a conjugate acid of a weak base. Therefore it is acidic.

a graduated cylinder.

explanation:

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.