) Core electrons shield valence electrons so that they experience an effective nuclear charge (Zeff) rather than the full nuclear charge. Given that the first ionization potential of Li is 5.39 eV, estimate the effective nuclear charge experienced by the 2s electron in Li.

1.26

Explanation:

From

I= 13.60 Z^2/n^2

Where:

I= ionization potential

Z= effective nuclear charge

n= energy level

Z= √In^2/13.60

Z= √ 5.39×2^2/13.60

Z = 1.26

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