Find the equilibrium constant for the reaction: A(g) + B(g) ⇌ 2C(g) at 25°C when k equals 1.4 × 10-12 M-1s-1 for the reaction: A(g) + B(g) → 2C(g) at 25°C and k equals 2.7 × 10-13 M-1s-1 for the reaction: 2C(g) → A(g) + B(g) at 25°C.

Answer : The equilibrium constant for the following reaction is, 5.2

Explanation :

The forward chemical reaction is:

The backward chemical reaction is:

Now we have to calculate the equilibrium constant for the following reaction.

The expression for equilibrium constant will be:

Therefore, the equilibrium constant for the following reaction is, 5.2

level 4 to level 2 : ))

i believe the answer is three water molecules