E. coli is cultivated in continuous culture under aerobic conditions with a glucose limitation. When the system is operated at D = 0.2 h-1, determine the effluent glucose (S) and biomass concentrations (X) by using the following equations (S0 = 5 g/L):a) Monod equation: 휇휇푚푚푚푚푚푚= 0.25 h-1, Ks = 100 mg/L, 푌푌푋푋/푆푆푀푀 = 0.4 g X/g S;b) Contois equation: 휇휇푚푚푚푚푚푚= 0.25 h-1, 퐾퐾푠푠푚푚 = 0.04, 푌푌푋푋/푆푆푀푀= 0.4 g X/g SCompare and comment on the results. Why might they be different? [Hint: consider the different assumptions under which each equation operates]