How much heat is added if 0.2706g of water increases in temperature by 0.216 degree C?

0.25J

Explanation:

Given parameters:

Mass of water  = 0.2706g

temperature change  = 0.216°C

Unknown:

Amount of heat added  = ?

Solution:

The quantity of heat added to a substance is given by the expression below;

               H  = m c Δt

where m is the mass of the body

           c is the specific heat capacity

           Δt is the temperature change

specific heat capacity is a constant and for water the value is 4.2J/g°C

    Input the variables to solve for H;

                  H  = 0.2706 x 4.2 x 0.216   = 0.25J

calculate how many grams of ammonia can be produced from 4.21 grams of

n2 + 3h2 = 2nh3

my answer:

25.0g n2 x (1 mol/ 28.0gn2) x (2 mol nh3/ 1 mol n2) x (17.0g nh3/ 1 molnh3) = 30.36g n2

25.0g h2 x (1 mol h2/ 2.00g h2) x (2 mol nh3/ 3 mol h2) x (17.0g nh3/ 1 mol nh3) = 141.67g h2

lr = n2

the answer to your question is c.

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