A race car driver starts a race with his tires at 13.2 psi at a temperature of 25 C. What will the pressure in the tires be (in psi) when they heat up to 63 C?

P₂ = 14.88 psi

Explanation:

Given data:

Initial pressure of tires = 13.2 psi

Initial temperature = 25°C (25+273 = 298 K)

Final pressure in tires = ?

Final temperature = 63°C (63+273 = 336 K)

Solution:

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

13.2 / 298 K = P₂/336 K

P₂ = 13.2 psi × 336 K / 298 K

P₂ = 4435.2 psi. K /298 K

P₂ = 14.88 psi

d.) circle motion requires a force to give it a centripetal acceleration.