60.0 mL of 0.100 M Ca(OH)2 solution is mixed with 50.0 mL of 0.100 M HNO3. Calculate the volume of 0.100 M H2SO4 needed to neutralize the resulting mixture.

The volume of 0.100 M H₂SO₄ needed to neutralize the resulting mixture containing an excess of 10 ml of 0.100 M Ca(OH)₂  is 10 ml of 0.100 M H₂SO₄ .

Explanation:

Ca(OH)₂ + HNO₃ = Ca(NO₃)₂ + H₂O

From the above reaction;

1 mole of Ca(OH)₂ is required to neutralize 1 mole of HNO₃ also

0.1 mole of Ca(OH)₂ will be required to neutralize 0.1 mole of HNO₃

Since there is 60 ml of 0.100 M Ca(OH)₂ and  50.0 mL of 0.100 M HNO₃, then on completion of neutralization, there will be 10 ml of 0.100 M Ca(OH)₂ left to be consumed

When H₂SO₄ is added to the solution, the reaction will be as follows;

Ca(OH)₂ + H₂SO₄ → CaSO₄ + H₂O

Therefore we have;

1 mole of  H₂SO₄ is required to completely react with 1 mole of Ca(OH)₂

Hence,

0.1 mole of  H₂SO₄ will completely react with 0.1 mole of Ca(OH)₂

Therefore the volume of 0.100 M H₂SO₄  required to neutralize  the resulting mixture containing an excess of 10 ml of 0.100 M Ca(OH)₂  is 10 ml

explanation:

two years ago, when picking flowers in the mountains back of yosemite valley, i found a book. it was blotted and storm-beaten; all of its outer pages were mealy and crumbly. the paper seemed to dissolve like the snow beneath which it had been buried, however; many of the inner pages were well preserved. and although all were more or less stained and torn, whole chapters were easily readable. this is the condition of the great open book of yosemite glaciers today; its granite pages have been torn and blurred by the same storms that wasted the castaway book.

two years ago, when picking flowers in the mountains back of yosemite valley; i found a book. it was blotted and storm-beaten, all of its outer pages were mealy and crumbly. the paper seemed to dissolve like the snow beneath which it had been buried, however, many of the inner pages were well preserved. and although all were more or less stained and torn; whole chapters were easily readable. this is the condition of the great open book of yosemite glaciers today, its granite pages have been torn and blurred by the same storms that wasted the castaway book.

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o