Given a diprotic acid, H2A, with two ionization constants of Ka1 = 2.4x10^-4 and Ka2 = 4.9x10^-11, calculate the pH for 0.182 M solution of NaHA.

pH = 6.964 which rounds to 7.0 if 2 sig figs

Explanation:

Ka₁ * Ka₂ = x

2.4x10⁻⁴ * 4.9x10⁻¹¹ = 1.176x10⁻¹⁴

√1.176x10⁻¹⁴ = 1.084435337x10⁻⁷

pH= -log[H⁺]

pH= -log[1.084435337x10⁻⁷]

pH= 6.964796339

explanation:

venn diagram is pictorial representation with of circles showing the relation between two finite sets or things. the intersection part of two circles conveys the relation present in between those sets or things.

here in the venn diagram of sand and salt two circles represent sand and salt. but the area falling under the intersection of these circle represents the mixture of sand and salt.

so, in a venn diagram the mixture will be placed in a middle that is in between the intersection of two circles.

the answers are

c and c