A system consisting of 57.5 g of liquid water at 298 K is heated using an immersion heater at a constant pressure of 1.00 bar. If a current of 1.50 A passes through the 10.0-ohm resistor for 150 s, what is the final temperature of the water

Explanation:

Heat generated = I² Rt , I is current , R is resistance , t is time .

= 1.5 x 1.5 x 10 x 150

Q = 3375 J

Q = m s ΔT , m is mass , s is specific heat of water ,  ΔT is rise in temperature.

ΔT = Q /  m s

= 3375 / 57.5 x 4.2

= 14 k

Final temperature

= 298 + 14

= 312 k

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