How many moles of oxygen atoms are contained in the following?

A) 3.31 mil KMnO4
B)43.4 mol CO2
C)2.45e-2 mol CuSO4•5 H2O

For A: The moles of oxygen atoms are 13.24 moles

For B: The moles of oxygen atoms are 86.8 moles

For C: The moles of oxygen atoms are 0.2205 moles

Explanation:

1 mole of contains 1 mole of potassium atoms, 1 mole of manganese atoms and 4 moles of oxygen atoms

So, moles of oxygen atoms = (3.31 × 4) = 13.24 moles

1 mole of contains 1 mole of carbon atoms and 2 moles of oxygen atoms

So, moles of oxygen atoms = (43.4 × 2) = 86.8 moles

1 mole of contains 1 mole of copper atoms, 1 mole of sulfur atoms, 10 moles of hydrogen atoms and 9 moles of oxygen atoms

So, moles of oxygen atoms =

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

fe 55.85 g/mol and h2o 18.02 g/mol.