Which of the following will occur when a solution of Pb(NO3)2(aq) is mixed with a solution of KI(aq)?

A.) A precipitate of KNO3 will form; Pb2+ and I– are spectator ions.
B.) A precipitate of Pb(NO3)2 will form; K+ and I– are spectator ions.
C.) A precipitate of PbI2 will form; Pb2+ and I– are spectator ions.
D.) A precipitate of PbI2 will form; K+ and NO3– are spectator ions.
E.) No precipitate will form.

What will happen when Pb(NO3)2(aq) is mixed with a solution of KI(aq) is;

Option D; A precipitate of PbI2 will form; K+ and NO3– are spectator ions.

We want to find what will happen when Pb(NO3)2(aq) is mixed with a solution of KI(aq)

Let us write a balanced equation of this reaction.

Pb(NO3) 2 (aq) + 2KI(aq) = PbI2(s) + 2KNO3(aq)

To answer this question properly, we need to write an ionic equation of the balanced equation above.

Let us first list all the ions present which are;

Pb2+(aq) + 2NO3-(aq) and K+(aq) + I-(aq)

Writing the ionic equation now gives us;

Pb2+(aq) + 2NO3-(aq) + K+(aq) + I-(aq) = PbI2(s) + 2K+(aq) + 2NO3-(aq)

In this ionic equation, we see that it formed PbI2(s) which is a precipitate.

Now, the ions 2K+(aq) + 2NO3-(aq) are on the same side and as such are not participating in the reaction. Thus, they can be called spectator ions.

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When a solution of Pb(NO3)2(aq) is mixed with a solution of KI(aq), a precipitate of PbI₂ will form; K⁺ and NO₃⁻ are spectator ions.

Explanation:

When an aqueous solution of lead nitrate (Pb(NO₃)₂ is mixed with aqueous solution of potassium iodide (KI), then there is a precipitate formation of lead iodide (PbI₂), and the potassium  (K⁺) ion and nitrate (NO₃⁻) ion acts as spectator ions that is ions do not involved in the reaction.

The reaction can be represented as,

Pb(NO₃)₂(aq) + 2 KI (aq) → PbI₂(s) + 2KNO₃(aq)

The ionic equation can be written as,

Pb²⁺(aq) + 2 NO₃⁻(aq) + 2 K⁺(aq) + 2 I⁻(aq) →  PbI₂(s) + 2K⁺(aq) + 2NO₃⁻(aq)

On both sides of the equation, we have K⁺ and NO₃⁻ ions, which gets cancelled, and these 2 ions are called as spectator ions.

answer: c. the experiment shows that the red substance experienced a chemical change.

explanation: chemical change is the change in which chemical composition of the substance changes. physical change is the change in which there is no change in chemical composition.

chemical changes are accompanied by following changes:

a) precipitate formation

b) energy is released or absorbed

c) formation of bubbles

d) change in color

as it is given that the red color has disappeared and there is production of gas, it means the red substance has undergone a chemical change.

e

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explanation: