Problem PageQuestion Gaseous butane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 4.6 g of butane is mixed with 7.65 g of oxygen. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction. Round your answer to significant digits.

6.47 grams is the maximum mass of carbon dioxide that could be produced by the chemical reaction.

Explanation:

Moles of butane =

Moles of oxygen gas =

According to reaction , 13 moles of oxygen gas reacts with 2 moles of butane,then 0.239 moles of oxygen gas will react with :

of butane.

From this we can see that butane is present in an excess amount and oxygen gas is present in limited amount. Hence, oxygen gas is a limiting reagent.

Since, oxygen gas is a limiting reagent which means that amount of carbon dioxide gas produce will depend upon moles of oxygen gas.

According to reaction, 13 moles of oxygen gas gives 8 moles of carbon dioxide, then 0.239 moles of oxygen gas will give:

Mass of 0.1471 moles of carbon dioxide gas:

0.147 mol × 44.01 g/mol = 6.47 g

6.47 grams is the maximum mass of carbon dioxide that could be produced by the chemical reaction.

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.