Moles of LiCL.
52.0 g of LiCl represents

52.0 g of LiCl represents 1.23 moles of compound

Explanation:

In order to determine the moles of LiCl, we need to know the molar mass of our compound

Molar mass LiCl = Molar mass Li + Molar mass Cl

Molar mass LiCl = 6.94 g/mol + 35.45 g/mol =42.39 g/mol

Now, we can do the conversion:

52 g . 1 mol / 42.39 g/mol = 1.23 moles

the electron configuration that you gave me has 16 electrons ergo it has 16 protons ergo it is the element sulfur.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2