Methane is burned with dry air in a steady-flow combustor. The volumetric analysis of the products on a dry basis is 5.2% CO2, 0.33% CO, 11.24% O2, and 83.23% N2. The methane and air enter the combustor at 298 K and 1 atm and the products exit at 1200 K and 1 atm. Determine (a) the air-fuel ratio, (b) the equivalence ratio, (c) the dew point of the product mixture, (d) the amount of energy transfer as heat (in kJ/kmol CH4), and (e) the entropy production rate during the combustion process (in kJ/kmol-K). The surroundings are at 298 K and 1 atm. Assume ideal gas behavior, and make allowance for variations in species specific heats with temperature.

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !

particle   p is an electron and particle q is a neutron

every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. therefore, there must be the same number of atoms of each element on each side of a chemical equation.