Calculate the mass of potassium in the sample : g Submit Answer Tries 0/3 Calculate the percent of potassium in the sample : % Submit Answer Tries 0/3 Calculate the volume of standard NaOH that reacted with iron : mL Submit Answer Tries 0/3 Calculate the mass of iron in the sample : g

Answer is explained below.

Explanation:

Calculate the mass of potassium in the sample :

1st equivalence point corresponds to K+ ;

mol K+ = moles of NaOH used in titration (from V1 ) = 0.100 mol/L * 6.00 ml/1000 ml/L = 0.00060 moles

mass of K+ in sample =  0.00060 moles* 39.1 g/mol = 0.02346 g

Calculate the percent of potassium in the sample :

mass of K+ in sample / mass of sample *100

0.02436 g / 0.195 g *100 = 12.03 %

Calculate the volume of standard NaOH that reacted with iron :

V2 -V1 = 16.40 ml - 6.00 ml = 10.40 mL

Calculate the mass of iron in the sample :

three moles of hydroxide ion are required to react with each mole of iron ion in the salt.

moles of Fe = 1/3* moles of NaOH used in titration (form V2 - V1) = 0.100 mol/L * 10.4 ml/1000 ml/L /3 = 0.000347 moles

mass of Fe in sample = (moles of Fe)(55.85 grams/mole) = 0.000347 moles*55.85 g/mol = 0.01936 g

Calculate the percent of iron in the sample :

mass of Fe in sample / mass of sample *100

0.01936 g / 0.195 g *100 = 9.93 %

the reaction mixture contains some ammonia, plus a lot of unreacted nitrogen and hydrogen. the mixture is cooled and compressed, causing the ammonia gas to condense into a liquid. the liquefied ammonia is separated and removed. the unreacted nitrogen and hydrogen are then recycled back into the reactor .

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml