After identifying the anions (negative ions), in each of the following
compounds, write the formula for the compound in either the soluble
beaker or insoluble box in the correct anion section, on the other page.
AgCl
NaCzH302
Lici
H2SO4
Pb(NO3)2
CaCO3
NaOH
Ca(OH)2
КОН
Cu(OH)2
CaSO4
HCI
(NH4)3PO4
Ca(NO3)2
MgCO3

idk what is it? is this a question that you know the answer or u dont

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o