What is the pOH of a 0.0010 M solution of calcium hydroxide (Ca(OH)2)
(the answer is not 2.40)

The answer to your question is pOH = 3.0

Explanation:

Data

pOH = 0.0010 M

Formula

pOH = -log [OH⁻]

pOH is the measure of the concentration of OH⁻ of a solution. It measures the alkalinity of a solution.

-Substitution

pOH = -log [0.0010]

-Simplification

pOH = -(-3)

-Result

pOH = 3

-Conclusion

The pOH of a solution 0.0010 M is 3.

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

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