Clutch Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 19.2 g of ethane is mixed with 35. g of oxygen. Calculate the minimum mass of ethane that could be left over by the chemical reaction. Round your answer to significant digits.

9.9 grams

Explanation:-

To calculate the moles, we use the equation:

a) moles of ethane

b) moles of oxygen

According to stoichiometry :

7 moles of oxygen require 2 moles of ethane

Thus 1.09 moles of oxygen require =  of ethane

Thus is the limiting reagent as it limits the formation of product. Ethane is the excess reagent.

Ethane left = (0.64-0.31) = 0.33 moles

Mass of

Thus 9.9 grams of ethane that could be left over by the chemical reaction

the electronic configuration of an atom with eight electrons is 1s²2s²2p⁴. the orbital diagrams are shown in the figure.

as per the hunds rule:

1. electrons tend to avoid being in the same orbital as per as practicable.

2. electrons in different orbitals of the same energy will have their spin parallel.

this can be illustrated from the multiplicity of the orbitals of the atom. as there are four electrons in the p orbital and p orbital has 3 sub-shells. the electrons can be fed in different ways as shown in the figure but the correct orbital diagram will be as per the hunds rule.

the answer is the first option

explanation:

just googled it m8. not that hard

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